跟读练习: Turing & The Halting Problem - Computerphile - 通过视频学习英语口语
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Today we're going to be talking about a problem in logic, and how in solving that problem,
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Alan Turing almost inadvertently invented the modern digital computer.
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So we start back at the beginning of the 20th century, where mathematicians had posed this problem.
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- Thank you.
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In logic, we're interested in finding, do these premises entail this conclusion?
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So premises are the bits you start off with in an argument.
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They are the bits you know at the beginning or your assumptions.
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And the conclusion is the bit you want to establish, the bit that you reason to with your argument.
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And we want to know, is there a test that will tell us, yes, for sure, these premises do or don't entail this conclusion?
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Is there an automatic way of finding out whether they do or whether they don't. So that's the problem.
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It's called the decision problem.
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and mathematicians wanted to find out Is there an answer to the decision problem for first order logic?
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That's the kind of logic you learn in philosophy or mathematics at university.
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So lots of mathematicians were trying to work out, is first order logic decidable?
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That is, can we automatically test whether the premises entail the conclusion?
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Alan Shuring was one of the first to discover that first order logic isn't decidable.
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I To prove this, It's really difficult conceptually,
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because you have to be able to show no possible program can give you the answer.
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But how do you do that?
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How do you show something about every possible program?
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You can't run through every program one by one.
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But Turing came up with a brilliant solution.
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Yeah.
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His idea goes something like this.
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Suppose we have a program and let's just draw it as a black box.
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It's going to take some inputs, and it's going to give us some outputs.
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our program is going to solve some problem.
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a problem like, do the premises entail the conclusion?
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We ask it a question and it will give us an answer: yes, or no?
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Now here's another question we can ask: Thank you.
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Let's look at all of those possible programs.
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And we're just thinking of them as black boxes at the moment.
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We might want to know, is this program Given a certain input, gonna give us an answer.
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Or is it going to trundle on forever and never give us an answer?
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That is, is it going to halt or is it not going to halt eventually?
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So think about your computer running.
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You want it to give you an answer.
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And whether it's a good answer or a bad answer, it's better than no answer.
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No answer would mean the computer trundles round forever and ever in a loop.
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And you would just never know whether it's going to finish today, tomorrow or never.
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So halting is good.
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So there's another question we can ask: Given some program and some inputs, will it ever halt?
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Now it turns out that our logical problem Do these premises entail this conclusion?
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is very similar to this halting problem.
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In fact, if we can solve the logical problem, then we can solve the halting problem.
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Will this program halt on this input?
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So the clever part of Turing's proof is to show that it's impossible for any machine, however clever it is, to solve the halting problem.
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That is to tell us whether a given machine with a given input will halt or not.
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And here's how we did it.
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Let's suppose we've got a machine or a program that solves the problem for us it solves the holding problem.
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Don't worry about how it works, let's just think of it as a black box, taking a description of a machine and an input, and giving us an answer.
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Yes it will halt or no it won't halt.
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Just suppose that's possible.
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Call that machine H for the halting problem.
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If you give me that machine, I can transform it into a different machine like this.
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I stick some extra bits on it so that If it gives me a yes answer, I make it loop forever without ever stopping.
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If it gives me a no answer on the other hand, it's gonna halt straight away.
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Let's call that big machine the whole thing.
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H plus.
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Now here's another question we can ask: what happens if I feed the whole machine into itself.
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So I'm going to put H plus Thank you in here and H + in here.
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So the question I'm now asking is, I'm feeding H + into itself.
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So I'm asking the question: Does H + halt?
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give an input H+.
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And here's where it all goes wrong.
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because If H + does halt, We get a yes answer.
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But then it loops forever, so it doesn't halt.
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On the other hand, if it doesn't halt, We get a no answer, but then it halts.
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So if it does halt, then it doesn't halt.
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But if it doesn't halt, then it does halt.
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Either way, we get a contradiction.
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It's a paradox.
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And what that shows is we started off assuming that we can solve the problem.
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we've ended up with a paradox.
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So our assumption was bad.
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It turns out there's no possible machine, no possible program that solves the halting problem.
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The really clever bit about Turing's idea is it doesn't matter what kind of program or machine it is.
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It doesn't matter whether it's An abstract algorithm, whether it's a real computer, a physical computer, it doesn't matter what it is.
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We've proved that no such program is possible.
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you Turing, as part of his argument, had to say a little bit about what's going on in these black boxes.
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And the idea is that every card represents an instruction in this Turing machine.
📺 同频道
✨ 推荐视频
本课的词汇与口语要点
这段视频共有 81 个句子、976 个单词可供跟读。 讲话部分时长为 6:14。 说话人语速自然,每分钟约 157 个词,接近日常对话。 83% 的单词属于英语最常用的 3,000 词,其余的词建议在练习前先学一下。
视频中的重点词汇
视频中 15 个值得学习的单词,附发音和释义:
| 单词 | 发音 | 释义 |
|---|---|---|
| hungry 形容词 | /ˈhʌŋ.ɡɹi/ | 飢餓 /饥饿, 餓 /饿 |
| solve 动词 | /sɒlv/ | 解決 /解决 |
| input 名词 | /ˈɪnpʊt/ | 輸入 /输入 |
| conclusion 名词 | /kənˈkluːʒən/ | 結束 /结束 |
| premise 名词 | /ˈpɹɛm.ɪs/ | 前提 |
| loop 名词 | /luːp/ | 圈, 環 /环 |
| assumption 名词 | /əˈsʌm(p).ʃ(ə)n/ | 假設 /假设 |
| paradox 名词 | /ˈpæ.ɹəˌdɒks/ | 悖論 /悖论, 矛盾 |
| establish 动词 | /ɪˈstæb.lɪʃ/ | 確定 /确定 |
| output 名词 | /ˈaʊtpʊt/ | 輸出 /输出 |
| discover 动词 | /dɪˈskʌvə/ | 發現 /发现, 發覺 /发觉 |
| automatic 形容词 | /ˌɔː.təˈmæt.ɪk/ | 自動的 /自动的 |
| mathematics 名词 | /mæθ(.ə)ˈmæt.ɪks/ | 數學 /数学, 算學 /算学 |
| abstract 名词 | /ˈæbˌstɹækt/ | 摘要 |
| instruction 名词 | /ɪnˈstɹʌkʃən/ | 教導 /教导 |
视频中出现的短语动词
| 单词 | 发音 | 释义 |
|---|---|---|
| find out 动词 | 找出, 查明 | |
| turn out 动词 | 原來 /原来 | |
| come up with 动词 | 想出, 提出 | |
| work out 动词 | /ˌwɝk ˈaʊt/ | 計算 /计算, 算出 |
需要注意的发音
说话人用了 25 次缩略和弱读形式,例如 doesn't, I'm, don't。请按听到的简短形式来说。
- “th” 音: mathematics /mæθ(.ə)ˈmæt.ɪks/, algorithm /ˈælɡəɹɪðm̩/, mathematician /ˌmæθ.(ə.)məˈtɪʃ.ən/
- “sh” 和 “zh” 音: conclusion /kənˈkluːʒən/, assumption /əˈsʌm(p).ʃ(ə)n/, establish /ɪˈstæb.lɪʃ/, instruction /ɪnˈstɹʌkʃən/, mathematician /ˌmæθ.(ə.)məˈtɪʃ.ən/
- 长单词——注意重音位置: automatic /ˌɔː.təˈmæt.ɪk/, mathematics /mæθ(.ə)ˈmæt.ɪks/, mathematician /ˌmæθ.(ə.)məˈtɪʃ.ən/, decidable [dɪˈsaɪdəbəɫ], conceptually /kənˈsɛp.tjʊə.li/
如何用这段视频练习
- 先完整听一遍视频,不要开口,记下不认识的单词。
- 先用 0.75 倍速逐句跟读,熟练之后再回到正常速度。
- 录下自己的声音并与原声对比,特别注意 hungry, solve, input 这类单词。
什么是跟读法?
跟读法 (Shadowing) 是一种有科学依据的语言学习技巧,最初开发用于专业口译员的培训,并由多语言者Alexander Arguelles博士普及。这个方法简单而强大:您在听英语母语原声的同时立即大声重复——就像是一个延迟1-2秒紧跟说话者的影子。与被动听力或语法练习不同,跟读法强迫您的大脑和口腔肌肉同时处理并模仿真实的讲话模式。研究表明它能显着提高发音准确性,语调,节奏,连读,听力理解和口语流利度——使其成为雅思口语备考和真实英语交流最有效的方法之一。








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