쉐도잉 연습: 1. Introduction to statistics - Lecture 1 - 영상으로 영어 말하기 배우기
레슨 만드는 중...
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Dear students, welcome.
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My name is Ludovico Biagi, I am professor in Politecnico di Milano.
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And with this slot of lectures I would provide you a general introduction to statistics
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and probabilities and what it is needed to better understand more complicated ideas relevant to geospatial intelligence.
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The slot of lectures on statistics will last about more or less five hours.
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It is split in several slots and each one's slot concerns a specific topic
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and each one's slot is accompanied by exercises that you can do by yourself.
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and questions to let you understand if you have completely understood what is contained in the lectures.
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First of all, I would start with a general outline about the following slides that we will see in the next slots.
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We will start with the general definition of probability, the general properties of probabilities,
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then we will introduce the idea of conditional probability
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and this leads to the definition of the theorem of bias
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and the idea of total probability and then we will move to the concept of independent events.
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After the discussion of probability we will move toward the idea of random variables.
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We will start in one dimension, so we will define what is a random variable,
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we will define what is the distribution and the density functions of a random variable, we will see some specific examples of random variables,
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because these examples are very important for the following.
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We will define what is the function of one random variable, and then we will see what is the mean and the variance of a random variable.
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Then we will move to random variables in two dimensions, I mean x and y.
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We will define them, we will see what is the joint density function,
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what are the marginal distributions of the two components of a random variable in two dimensions.
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again what is the mean the covariance, the propagation laws for the mean and the covariance,
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the conditional distributions and the concept of independence between the two components of a random variable in two dimensions.
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The next slot will be about the generalization to Rn dimensions.
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so again we will see how the properties of random variables in two dimensions can be extended to a general n-dimensional space.
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We will see also the differences in Rn with respect to R2.
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And finally, a slot will be devoted to the so-called asymptotic behavior of random variables
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that puts a very important link between the theory of probability and the practice of observations.
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I mean why and how the general theory of probabilities
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and random variables can be applied in the management and analysis of observations.
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Finally, we will see a particular example of estimator for random variables, that is least squares.
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So we will put the general position of the problem, we will see what are for least squares the estimation principles,
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what are the estimates provided by least squares, both of the unknowns and of the covariances of the estimated parameters.
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Then in the last, very last part, we will see what does it mean to make an hypothesis testing
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and in particular we will see how to apply this general principle to the global model
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and to the individual observations in least squares.
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So let's start with the probability and in the order we will see the axiomatic definition of probability,
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the properties of a probability, what is the conditional probability,
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what is the total probability of one event and what is the bias theorem.
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We are not going to prove theorems just to enunciate and discuss them and finally we will see what are independent events.
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So in general what are stochastic experiments and what is their modeling?
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Let's start with the definition of a probability model, we can call it capital omega.
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The elements of a probability model are called also experimental outcomes and we will denote them with the lower case omega.
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The subset of capital omega are named events.
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In this picture you see that in orange it is the complete set,
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so capital omega, and the white area is a specific event,
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capital A, named capital A.
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Just to complete the model we need clearly to assign probabilities to all the events capital A
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that compose the capital omega set.
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So we can start with the axiomatic definition of probability.
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Let's take an event capital A.
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The probability of capital A is a certain number
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that we can symbolize with the p of capital A that is related to capital A.
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This number must satisfy the following properties axioms.
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The probability of an event is not negative, so it is bigger or equal to zero.
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The probability of the whole set of events, so capital omega, is equal to one.
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Then let's take two exclusive events, capital A and capital B,
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then the probability of their union, the probability that they happen together,
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is given by the probability of A plus the probability of B.
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Let's generalize the idea of the tiered axiom.
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By looking to the picture we have again the capital omega set of events.
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Let's suppose you have three events in this case A, B and C that are depicted with the white, blue
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and red areas, the probability of A union B union C is equal to
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the probability of A plus the probability of B plus the probability of C.
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This can be extended to any finite number of terms
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and this could be extended also for an infinite but countably many terms.
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This is the axiom of infinite additivity that states that the union,
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the probability of the union of an infinite number of events a1, a2, etc, etc, etc,
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is simply given by the sum of probability of a1 plus
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probability of a2 plus up to an infinite sum on all these set of events.
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More and more about properties.
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The probability of the impossible event, or if you prefer the zero event, is equal to zero.
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Moreover, let's look to the picture.
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You have capital omega, that is the whole set of possible events.
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You have the event A, again the white area.
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The complementary of A is defined as omega minus A, so all the events that are not A,
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and the probability of the complementary of A is 1 minus the probability of A.
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Now the probability of an event A is always between 0 and 1,
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0 for the impossible event and 1 for capital omega taken as a wall.
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Let's consider two events, B and A, and let's suppose that B is a subset of A.
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In this case, the probability of B is smaller or equal to the probability of A.
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Now let's suppose A and B, on the contrary, are two events with an intersection exactly in the picture.
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You see there is an orange omega, in white A, in blue B, and you see that they have an intersection.
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In this case the probability of A union B is exactly
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equal to the probability of A plus the probability of B minus the probability of their intersection.
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An experiment, capital omega, is specified in terms of the probabilities of all the events that compose the experiment.
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However, considering the previous axioms, we don't need to assign probabilities to every event.
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In particular, if capital omega consists of n outcomes,
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the experiment is specified in terms of the probabilities of the elementary events lowercase omega.
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The foregoing can also also, if capital omega consists of a countable number of outcomes.
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On the contrary, it doesn't hold when the elements of capital omega are not countable,
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for example the real valued points of an interval that is not countable.
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Let's consider an experiment that can output a certain number capital N of outcomes.
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These outcomes are said to be equally likely
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when they have exactly the same probability and each one probability is exactly equal to 1 over capital N.
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Now let's suppose that an event consists of NA outcomes.
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Then the probability of A can be simply written as Na over N.
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As an example let's consider the classical coin or the classical die.
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We can say that the coin is fair when its outcomes are equally likely,
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that is, the probability of heads is equal to the probability of tails and they are both equal to 1 over 2.
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and let's look to a die, a die has six possible outcomes from one to six,
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they are equally likely when probability of one is equal to probability of two up to probability of six,
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and this clearly means that each one probability is one over six now let's suppose you toss a coin twice,
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so you can have four different possible outcomes, events.
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Indeed, the capital omega is composed by a head head,
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head tail, tail head and tail tail.
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If these four outcomes are equally likely, then each one of them has probability equal to 1 over 4.
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Now let's suppose that you want to check the probability of the event A that both the second toss,
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pardon, has outcome as tail.
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This event A is generated by age T or TT.
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So two possible outcomes generate the event and so the probability of the event is 1 over 2.
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Now let's suppose that our set capital omega consists not of a number countable of outcomes
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but of a non-countable number of outcomes.
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For example the possible points in the real line, in this case capital omega is defined from minus infinite to plus infinite.
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In this case the experiment can be specified not in term of a probability but in term of a density function.
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Density function alpha is named in this slide is always bigger
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or equal to zero and integral between minus infinite and plus infinite of alpha is equal to 1,
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and in particular alpha is such that the probability
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that an outcome is comprised between a minimum value a
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and the maximum value b is given by the integral from a to b of alpha in dt.
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Now we can move to the idea and the properties of the conditional probability.
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Let's take any event M such that the probability of M is bigger than zero,
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strictly bigger than zero, and let's give another event A.
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We can compute the ratio probability of A intersection M divided by probability of M.
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You see in the picture in the bottom of the slide the example you have capital you have m in red,
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you have a in gray and they have an intersection.
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The ratio we have just defined is called a conditional probability of a assuming
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that m happened and it is denoted by the symbol probability of a given m
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and okay and it is the ratio of p intersection m divided by m.
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The meaning of conditional probability can be simplified as follows.
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You know that an event m happened,
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you just ask what is the probability that given m, a happens.
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The properties of the conditional probability are the following.
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Let's take again an event M
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and as a range as a ranges over all the events of capital omega we have
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that the probability of A given M is always bigger
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or equal to zero the probability of omega given M is equal to 1,
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and in particular, they take two different events, A and B.
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In case the intersection between A and B is void, we can write
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that the probability of A union B given M is the
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probability of A given m plus the probability of b given m.
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For example, let's take again the example of a die.
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We remember that the possible outcomes of a die are six, exactly from one to six.
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we want to determine the probability to obtain the outcome 2 assuming that an even outcome is given.
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So the probability of M, probability of even, is 1 over 2.
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The probability of 2 given even is the probability of A intersection M divided by the probability of M.
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The probability of A intersection M is 1 over 6, the probability of M is 3 over 6,
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so the probability of A given M is 1 over 3.
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In the picture in the bottom of the slide you see exactly the example, capital omega,
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m that is the set of even outcomes 2 4
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and 6 and a that is the only one outcome equal to 2.
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Now let's move to the concept of total probability
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and the theorem of bias that is very important for many many many applications.
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Now let's suppose to have a partition of capital omega.
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I mean that we have a set of events a1, a2, up to a m,
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such that the intersection between ae and aj is zero for each couple of ej,
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and the union of all the events a is the whole capital omega.
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Now let's suppose that you have an event B.
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The probability of B can be written as the probability of B given A1
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that multiplies the probability of A1 plus the probability of B
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given A2 multiplied by the probability of A2 summed up to the whole set of events A,
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so summed up to AM.
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So let's see the idea with a simple example.
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We have a political poll and we have recorded the following results.
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Among all the voters, 70% are male and 30% are female.
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Among males, 40% are Republican and 60% are Democrats.
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Among families 45% are Republican and 55% are Democrats.
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You need to find the probability that a voter selected at random is Republican.
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So from a graphical point of view, you see in the picture the set capital omega all the
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votes the orange set is split by a line into male
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and female voters and the outcomes are split in a set
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that is again orange of republicans and a red set of Democrats that are clearly shared between families and males.
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So the probability of a male voter is 0.7,
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the probability of a family voter is 0.3, the probability of a Republican given
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m is 0.4 the probability of R given F is 0.45
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so the probability of R is the probability of R given
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M multiplied by the probability of M plus the probability of R given F multiplied by the probability of F.
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If you make the computation, you find that it is equal to 0.415, that is 41.5%.
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Now a very important theorem that we are not going to prove
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but just to discuss let's suppose that you have a partition of capital omega
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and we call this partition again a1 a2 up to a m it means
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that the their intersection is void for each couple
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and their union is the wall omega now let's suppose
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that you have another event b
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that in the picture is depicted as the red area
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and the probability of a given a given b so probability of ae given b
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is equal to the probability of b given ae
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that multiplies the probability of ae divided by the sum of probability of b given ae
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that multiplies probability of ae summed on all the a events,
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so summed on all the m a events.
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And with the help of two coins we can depict an example.
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Let's suppose we have two coins a and b.
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Coin a is fair, so the probability of head is equal to the probability of tail
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while coin of b is loaded with a probability for s
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that it is 2 over 3
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so probability of tail for b is 1 over 3 let's
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suppose you pick up one of the coin at random without knowing
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if it is a or b let's suppose you toss it
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and the outcome is s what is the probability that we picked the fair coin.
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So the probability can be computed as probability of F given add,
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so probability of add given A
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that multiplies probability of A over the probability of edge given A
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that multiplies probability of A plus probability of edge given B multiplied by probability of b.
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You make all the computations and you find that the probability is 3 over 7.
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Now let's move to the idea of independent events.
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We have two events, a and b.
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They are called statistically independent when the probability of their intersection is exactly equal to the product of their individual probabilities.
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So from a mathematical point of view we can write
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that probability of A intersection B is equal to probability of A that multiplies probability of B.
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What happens when two events are statistically independent for conditional probabilities?
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okay the probability of A given B
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that is defined as the probability of A intersection B divided
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by probability of B is equal to probability of A
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that multiplies probability of B divided by probability of B
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that is clearly equal to probability of A in the same way we see
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that probability of B given A is simply given by probability of B.
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Again let's help with a simple example.
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Let's suppose we have a fair coin and a fair die and let's suppose we toss both of them.
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Clearly the two experiments are independent.
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So let's suppose we want to compute the probability
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that 5 shows on the die and the output of coin is 8
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so the probability of the
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that the two outcomes happen together is the probability of the intersection
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that in this case because of the independence is the product of the individual probabilities
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and so we have 1 over 12 so this ends
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this first set of slides about statistics and at the end we find questions
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that allow you to self-evaluate yourselves i mean
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if you are able to answer to the questions you have
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understood the ideas on the contrary case it is better you try to look again to the lecture
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so the first question is what is a stochastic experiment outcome
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and what is an event the second question is what is
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the set capital omega of a probability space the third question
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is what is the set how it is defined the set of all the possible events
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and what are the properties of this set now you should be able to give the axiomatic definition of probability
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and now let assume
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that the set omega is discrete is it sufficient to assign
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the probability to each outcome to define it why it is the answer give an example of uniform distribution of probability
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possibly not the coin or the die, if the set capital omega is continuous,
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how we can specify the probability of an event,
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give the definition of conditional probability and the definition of of stochastically independent events,
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what is a partition of capital omega, and discuss the bias theorem.
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Moreover, in the exercises folder of this set of lectures,
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you will find a few very simple exercises that you should try to solve by yourself.
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Thank you.
✨ 추천 영상
统計학 입문 강의의 맥락과 배경
이 비디오는 밀라노 폴리테크니코의 루도비코 비아기 교수가 진행하는 "통계학 입문" 강의 첫 번째 부분입니다. 강의는 약 5시간에 걸쳐 확률과 통계, 확률변수, 최소제곱법 등의 주제를 다루며, 각 섹션마다 연습문제와 질문이 포함되어 이해도를 확인할 수 있습니다. 지리공간 지능과 관련된 복잡한 개념을 이해하기 위한 기초를 다지는 것이 목표입니다.
일상 커뮤니케이션에 유용한 5가지 표현
- "provide you a general introduction" - 일반적인 소개를 해드립니다. 새로운 주제를 시작할 때 자주 사용되는 표현입니다.
- "split in several slots" - 여러 부분으로 나누어집니다. 내용을 구조화할 때 유용합니다.
- "accompanied by exercises" - 연습문제와 함께 제공됩니다. 학습 자료를 설명할 때 쓰입니다.
- "leads to the definition of" - ...의 정의로 이어집니다. 논리적 흐름을 설명할 때 사용합니다.
- "put a very important link between" - ...사이에 중요한 연결고리를 만들어줍니다. 두 가지 개념의 관계를 강조할 때 유용합니다.
쉐도잉 연습 가이드: 이 비디오를 활용한 방법
영상 영어 공부에서 쉐도잉은 발음과 리듬을 연습하는 좋은 방법입니다. 특히 이 강의는 학술적인 용어가 많아 영어 발음 교정에 효과적입니다. 다음 단계로 연습해보세요:
- 1회차: 영상만 듣고 내용 이해하기 - 강의의 전반적인 흐름을 파악하고, 중요한 용어들을 눈에 익히세요.
- 2회차: 발음에 집중하며 반복하기 - "probability", "random variables" 등 어려운 단어의 발음을 주의깊게 듣고 따라하세요. shadow speak 기술을 사용해 말하기 속도와 강세를 맞춰보세요.
- 3회차: 문장 구조 분석하기 - 긴 문장을 구성하는 방법을 살펴보세요. "We will start with the general definition of probability, the general properties of probabilities, then we will introduce..."와 같은 구조를 분해해 연습하면, 복잡한 표현도 자연스럽게 사용할 수 있습니다.
- 4회차: 자신의 말로 재구성하기 - 강의 내용을 간단히 요약해 말해보세요. 이 과정에서 학습한 표현을 실제로 사용해 봄으로써 기억에 남게 됩니다.
shadowspeaks를 통해 꾸준히 연습하면, 학술 영어 실력뿐만 아니라 일상 영어에도 자신감을 갖게 될 것입니다.
쉐도잉이란? 영어 실력을 빠르게 키우는 과학적 방법
쉐도잉(Shadowing)은 원래 전문 통역사 훈련을 위해 개발된 언어 학습 기법으로, 다언어 학자인 Dr. Alexander Arguelles에 의해 대중화된 방법입니다. 핵심 원리는 간단하지만 매우 강력합니다: 원어민의 영어를 들으면서 1~2초의 짧은 지연으로 즉시 소리 내어 따라 말하는 것——마치 '그림자(shadow)'처럼 화자를 따라가는 것입니다. 문법 공부나 수동적인 청취와 달리, 쉐도잉은 뇌와 입 근육이 동시에 실시간으로 영어를 처리하고 재현하도록 훈련합니다. 연구에 따르면 이 방법은 발음 정확도, 억양, 리듬, 연음, 청취력, 말하기 유창성을 크게 향상시킵니다. IELTS 스피킹 준비와 자연스러운 영어 소통을 원하는 분들에게 특히 효과적입니다.











