Shadowing Practice: 1. Introduction to statistics - Lecture 1 - Learn English Speaking with Video

Ders oluşturuluyor...
1
Dear students, welcome.
2
My name is Ludovico Biagi, I am professor in Politecnico di Milano.
3
And with this slot of lectures I would provide you a general introduction to statistics
4
and probabilities and what it is needed to better understand more complicated ideas relevant to geospatial intelligence.
5
The slot of lectures on statistics will last about more or less five hours.
6
It is split in several slots and each one's slot concerns a specific topic
7
and each one's slot is accompanied by exercises that you can do by yourself.
8
and questions to let you understand if you have completely understood what is contained in the lectures.
9
First of all, I would start with a general outline about the following slides that we will see in the next slots.
10
We will start with the general definition of probability, the general properties of probabilities,
11
then we will introduce the idea of conditional probability
12
and this leads to the definition of the theorem of bias
13
and the idea of total probability and then we will move to the concept of independent events.
14
After the discussion of probability we will move toward the idea of random variables.
15
We will start in one dimension, so we will define what is a random variable,
16
we will define what is the distribution and the density functions of a random variable, we will see some specific examples of random variables,
17
because these examples are very important for the following.
18
We will define what is the function of one random variable, and then we will see what is the mean and the variance of a random variable.
19
Then we will move to random variables in two dimensions, I mean x and y.
20
We will define them, we will see what is the joint density function,
21
what are the marginal distributions of the two components of a random variable in two dimensions.
22
again what is the mean the covariance, the propagation laws for the mean and the covariance,
23
the conditional distributions and the concept of independence between the two components of a random variable in two dimensions.
24
The next slot will be about the generalization to Rn dimensions.
25
so again we will see how the properties of random variables in two dimensions can be extended to a general n-dimensional space.
26
We will see also the differences in Rn with respect to R2.
27
And finally, a slot will be devoted to the so-called asymptotic behavior of random variables
28
that puts a very important link between the theory of probability and the practice of observations.
29
I mean why and how the general theory of probabilities
30
and random variables can be applied in the management and analysis of observations.
31
Finally, we will see a particular example of estimator for random variables, that is least squares.
32
So we will put the general position of the problem, we will see what are for least squares the estimation principles,
33
what are the estimates provided by least squares, both of the unknowns and of the covariances of the estimated parameters.
34
Then in the last, very last part, we will see what does it mean to make an hypothesis testing
35
and in particular we will see how to apply this general principle to the global model
36
and to the individual observations in least squares.
37
So let's start with the probability and in the order we will see the axiomatic definition of probability,
38
the properties of a probability, what is the conditional probability,
39
what is the total probability of one event and what is the bias theorem.
40
We are not going to prove theorems just to enunciate and discuss them and finally we will see what are independent events.
41
So in general what are stochastic experiments and what is their modeling?
42
Let's start with the definition of a probability model, we can call it capital omega.
43
The elements of a probability model are called also experimental outcomes and we will denote them with the lower case omega.
44
The subset of capital omega are named events.
45
In this picture you see that in orange it is the complete set,
46
so capital omega, and the white area is a specific event,
47
capital A, named capital A.
48
Just to complete the model we need clearly to assign probabilities to all the events capital A
49
that compose the capital omega set.
50
So we can start with the axiomatic definition of probability.
51
Let's take an event capital A.
52
The probability of capital A is a certain number
53
that we can symbolize with the p of capital A that is related to capital A.
54
This number must satisfy the following properties axioms.
55
The probability of an event is not negative, so it is bigger or equal to zero.
56
The probability of the whole set of events, so capital omega, is equal to one.
57
Then let's take two exclusive events, capital A and capital B,
58
then the probability of their union, the probability that they happen together,
59
is given by the probability of A plus the probability of B.
60
Let's generalize the idea of the tiered axiom.
61
By looking to the picture we have again the capital omega set of events.
62
Let's suppose you have three events in this case A, B and C that are depicted with the white, blue
63
and red areas, the probability of A union B union C is equal to
64
the probability of A plus the probability of B plus the probability of C.
65
This can be extended to any finite number of terms
66
and this could be extended also for an infinite but countably many terms.
67
This is the axiom of infinite additivity that states that the union,
68
the probability of the union of an infinite number of events a1, a2, etc, etc, etc,
69
is simply given by the sum of probability of a1 plus
70
probability of a2 plus up to an infinite sum on all these set of events.
71
More and more about properties.
72
The probability of the impossible event, or if you prefer the zero event, is equal to zero.
73
Moreover, let's look to the picture.
74
You have capital omega, that is the whole set of possible events.
75
You have the event A, again the white area.
76
The complementary of A is defined as omega minus A, so all the events that are not A,
77
and the probability of the complementary of A is 1 minus the probability of A.
78
Now the probability of an event A is always between 0 and 1,
79
0 for the impossible event and 1 for capital omega taken as a wall.
80
Let's consider two events, B and A, and let's suppose that B is a subset of A.
81
In this case, the probability of B is smaller or equal to the probability of A.
82
Now let's suppose A and B, on the contrary, are two events with an intersection exactly in the picture.
83
You see there is an orange omega, in white A, in blue B, and you see that they have an intersection.
84
In this case the probability of A union B is exactly
85
equal to the probability of A plus the probability of B minus the probability of their intersection.
86
An experiment, capital omega, is specified in terms of the probabilities of all the events that compose the experiment.
87
However, considering the previous axioms, we don't need to assign probabilities to every event.
88
In particular, if capital omega consists of n outcomes,
89
the experiment is specified in terms of the probabilities of the elementary events lowercase omega.
90
The foregoing can also also, if capital omega consists of a countable number of outcomes.
91
On the contrary, it doesn't hold when the elements of capital omega are not countable,
92
for example the real valued points of an interval that is not countable.
93
Let's consider an experiment that can output a certain number capital N of outcomes.
94
These outcomes are said to be equally likely
95
when they have exactly the same probability and each one probability is exactly equal to 1 over capital N.
96
Now let's suppose that an event consists of NA outcomes.
97
Then the probability of A can be simply written as Na over N.
98
As an example let's consider the classical coin or the classical die.
99
We can say that the coin is fair when its outcomes are equally likely,
100
that is, the probability of heads is equal to the probability of tails and they are both equal to 1 over 2.
101
and let's look to a die, a die has six possible outcomes from one to six,
102
they are equally likely when probability of one is equal to probability of two up to probability of six,
103
and this clearly means that each one probability is one over six now let's suppose you toss a coin twice,
104
so you can have four different possible outcomes, events.
105
Indeed, the capital omega is composed by a head head,
106
head tail, tail head and tail tail.
107
If these four outcomes are equally likely, then each one of them has probability equal to 1 over 4.
108
Now let's suppose that you want to check the probability of the event A that both the second toss,
109
pardon, has outcome as tail.
110
This event A is generated by age T or TT.
111
So two possible outcomes generate the event and so the probability of the event is 1 over 2.
112
Now let's suppose that our set capital omega consists not of a number countable of outcomes
113
but of a non-countable number of outcomes.
114
For example the possible points in the real line, in this case capital omega is defined from minus infinite to plus infinite.
115
In this case the experiment can be specified not in term of a probability but in term of a density function.
116
Density function alpha is named in this slide is always bigger
117
or equal to zero and integral between minus infinite and plus infinite of alpha is equal to 1,
118
and in particular alpha is such that the probability
119
that an outcome is comprised between a minimum value a
120
and the maximum value b is given by the integral from a to b of alpha in dt.
121
Now we can move to the idea and the properties of the conditional probability.
122
Let's take any event M such that the probability of M is bigger than zero,
123
strictly bigger than zero, and let's give another event A.
124
We can compute the ratio probability of A intersection M divided by probability of M.
125
You see in the picture in the bottom of the slide the example you have capital you have m in red,
126
you have a in gray and they have an intersection.
127
The ratio we have just defined is called a conditional probability of a assuming
128
that m happened and it is denoted by the symbol probability of a given m
129
and okay and it is the ratio of p intersection m divided by m.
130
The meaning of conditional probability can be simplified as follows.
131
You know that an event m happened,
132
you just ask what is the probability that given m, a happens.
133
The properties of the conditional probability are the following.
134
Let's take again an event M
135
and as a range as a ranges over all the events of capital omega we have
136
that the probability of A given M is always bigger
137
or equal to zero the probability of omega given M is equal to 1,
138
and in particular, they take two different events, A and B.
139
In case the intersection between A and B is void, we can write
140
that the probability of A union B given M is the
141
probability of A given m plus the probability of b given m.
142
For example, let's take again the example of a die.
143
We remember that the possible outcomes of a die are six, exactly from one to six.
144
we want to determine the probability to obtain the outcome 2 assuming that an even outcome is given.
145
So the probability of M, probability of even, is 1 over 2.
146
The probability of 2 given even is the probability of A intersection M divided by the probability of M.
147
The probability of A intersection M is 1 over 6, the probability of M is 3 over 6,
148
so the probability of A given M is 1 over 3.
149
In the picture in the bottom of the slide you see exactly the example, capital omega,
150
m that is the set of even outcomes 2 4
151
and 6 and a that is the only one outcome equal to 2.
152
Now let's move to the concept of total probability
153
and the theorem of bias that is very important for many many many applications.
154
Now let's suppose to have a partition of capital omega.
155
I mean that we have a set of events a1, a2, up to a m,
156
such that the intersection between ae and aj is zero for each couple of ej,
157
and the union of all the events a is the whole capital omega.
158
Now let's suppose that you have an event B.
159
The probability of B can be written as the probability of B given A1
160
that multiplies the probability of A1 plus the probability of B
161
given A2 multiplied by the probability of A2 summed up to the whole set of events A,
162
so summed up to AM.
163
So let's see the idea with a simple example.
164
We have a political poll and we have recorded the following results.
165
Among all the voters, 70% are male and 30% are female.
166
Among males, 40% are Republican and 60% are Democrats.
167
Among families 45% are Republican and 55% are Democrats.
168
You need to find the probability that a voter selected at random is Republican.
169
So from a graphical point of view, you see in the picture the set capital omega all the
170
votes the orange set is split by a line into male
171
and female voters and the outcomes are split in a set
172
that is again orange of republicans and a red set of Democrats that are clearly shared between families and males.
173
So the probability of a male voter is 0.7,
174
the probability of a family voter is 0.3, the probability of a Republican given
175
m is 0.4 the probability of R given F is 0.45
176
so the probability of R is the probability of R given
177
M multiplied by the probability of M plus the probability of R given F multiplied by the probability of F.
178
If you make the computation, you find that it is equal to 0.415, that is 41.5%.
179
Now a very important theorem that we are not going to prove
180
but just to discuss let's suppose that you have a partition of capital omega
181
and we call this partition again a1 a2 up to a m it means
182
that the their intersection is void for each couple
183
and their union is the wall omega now let's suppose
184
that you have another event b
185
that in the picture is depicted as the red area
186
and the probability of a given a given b so probability of ae given b
187
is equal to the probability of b given ae
188
that multiplies the probability of ae divided by the sum of probability of b given ae
189
that multiplies probability of ae summed on all the a events,
190
so summed on all the m a events.
191
And with the help of two coins we can depict an example.
192
Let's suppose we have two coins a and b.
193
Coin a is fair, so the probability of head is equal to the probability of tail
194
while coin of b is loaded with a probability for s
195
that it is 2 over 3
196
so probability of tail for b is 1 over 3 let's
197
suppose you pick up one of the coin at random without knowing
198
if it is a or b let's suppose you toss it
199
and the outcome is s what is the probability that we picked the fair coin.
200
So the probability can be computed as probability of F given add,
201
so probability of add given A
202
that multiplies probability of A over the probability of edge given A
203
that multiplies probability of A plus probability of edge given B multiplied by probability of b.
204
You make all the computations and you find that the probability is 3 over 7.
205
Now let's move to the idea of independent events.
206
We have two events, a and b.
207
They are called statistically independent when the probability of their intersection is exactly equal to the product of their individual probabilities.
208
So from a mathematical point of view we can write
209
that probability of A intersection B is equal to probability of A that multiplies probability of B.
210
What happens when two events are statistically independent for conditional probabilities?
211
okay the probability of A given B
212
that is defined as the probability of A intersection B divided
213
by probability of B is equal to probability of A
214
that multiplies probability of B divided by probability of B
215
that is clearly equal to probability of A in the same way we see
216
that probability of B given A is simply given by probability of B.
217
Again let's help with a simple example.
218
Let's suppose we have a fair coin and a fair die and let's suppose we toss both of them.
219
Clearly the two experiments are independent.
220
So let's suppose we want to compute the probability
221
that 5 shows on the die and the output of coin is 8
222
so the probability of the
223
that the two outcomes happen together is the probability of the intersection
224
that in this case because of the independence is the product of the individual probabilities
225
and so we have 1 over 12 so this ends
226
this first set of slides about statistics and at the end we find questions
227
that allow you to self-evaluate yourselves i mean
228
if you are able to answer to the questions you have
229
understood the ideas on the contrary case it is better you try to look again to the lecture
230
so the first question is what is a stochastic experiment outcome
231
and what is an event the second question is what is
232
the set capital omega of a probability space the third question
233
is what is the set how it is defined the set of all the possible events
234
and what are the properties of this set now you should be able to give the axiomatic definition of probability
235
and now let assume
236
that the set omega is discrete is it sufficient to assign
237
the probability to each outcome to define it why it is the answer give an example of uniform distribution of probability
238
possibly not the coin or the die, if the set capital omega is continuous,
239
how we can specify the probability of an event,
240
give the definition of conditional probability and the definition of of stochastically independent events,
241
what is a partition of capital omega, and discuss the bias theorem.
242
Moreover, in the exercises folder of this set of lectures,
243
you will find a few very simple exercises that you should try to solve by yourself.
244
Thank you.

Bu dersin kelimeleri ve konuşma notları

Bu C1 seviyesindeki konuşma dersi “1. Introduction to statistics - Lecture 1” videosuna dayanıyor. En çok tekrarlanan kelimeler: probability, event, capital, omega, outcome. Bu videoda gölgeleme çalışması için 244 cümle ve 3146 kelime var. Konuşma bölümü 26:38 sürüyor. Konuşmacı dakikada yaklaşık 118 kelimelik dengeli bir hızla konuşuyor; gölgeleme için rahat bir tempo. Kelimelerin yalnızca %76’i İngilizcede en sık kullanılan 3.000 kelime arasında, bu yüzden kelime dağarcığı zorlayıcı.

Bu videodaki önemli kelimeler

Videodaki en ileri düzey 15 kelime, telaffuzu ve anlamıyla:

KelimeTelaffuzAnlam
omega isim/oʊˈmeɪ.ɡə/omega
intersection isim/ˈɪntəɹˌsɛkʃən/kesişme
multiply fiil/ˈmʌltɪplaɪ/çarpmak
conditional isim/kənˈdɪʃ.ə.nəl/koşul bileşik zamanı, şart bileşik zamanı
theorem isim/ˈθiərəm/teorem
minus/ˈmaɪ.nəs/eksi
axiom isim/ˈæk.si.əm/aksiyom
partition isim/pɑɹˈtɪ.ʃən/bölme
compose fiil/kəmˈpəʊz/bestelemek
compute fiil/kəmˈpjuːt/hesaplamak
covariance isim/koʊˈvæɹ.i.əns/kovaryans
depict fiil/dɪˈpɪkt/tasvir etmek
discreet sıfat/dɪˈskɹiːt/ölçülü
enunciate fiil/ɪˈnʌnsiˌeɪt/beyan etmek, bildirmek
generalization isimjeneralizasyon

Tekrar etmeye değer cümleler

Videodan, günlük konuşmada yeniden kullanabileceğiniz kısa ve tam cümleler:

  • Let's generalize the idea of the tiered axiom.
  • Moreover, let's look to the picture.
  • Let's suppose we have two coins a and b.

Bu videodaki dil bilgisi

Konuşmacının en çok kullandığı yapılar, videodaki sözcüklerin aynısıyla:

YapıVideoda
Edilgen yapı be + fiilin üçüncü hâli — kimin yaptığı değil, ne olduğu önemliis needed · is split · is accompanied
Present perfect have/has + fiilin üçüncü hâli — geçmişte olan ama şimdi de önemli olan bir eylemhave just defined · have recorded

Dikkat edilecek telaffuzlar

  • “th” sesleri: theorem /ˈθiərəm/, hypothesis /haɪˈpɒθɪsɪs/, mathematical /ˌmæθ(.ə)ˈmæt.ɪ.kəl/
  • “sh” ve “zh” sesleri: intersection /ˈɪntəɹˌsɛkʃən/, conditional /kənˈdɪʃ.ə.nəl/, dimension /daɪˈmɛn.ʃən/, partition /pɑɹˈtɪ.ʃən/, computation /ˌkɑmpjʊˈteɪʃn̩/
  • Uzun kelimeler — vurguyu doğru yere koyun: probability /ˌpɹɑ.bəˈbɪl.ə.ti/, intersection /ˈɪntəɹˌsɛkʃən/, conditional /kənˈdɪʃ.ə.nəl/, axiomatic /ˌæk.si.əˈmæt.ɪk/, covariance /koʊˈvæɹ.i.əns/

Türkçe konuşanların zorlandığı sesler:

  • Kelime başındaki ünsüz kümesi — araya ünlü eklemeyin: probability /ˌpɹɑ.bəˈbɪl.ə.ti/, slot /slɑt/, specify /ˈspɛs.əˌfaɪ/, stochastic /stəˈkæstɪk/, statistically /stəˈtɪs.tɪ.kə.li/
  • /æ/ — “e”den daha açık: axiom /ˈæk.si.əm/, axiomatic /ˌæk.si.əˈmæt.ɪk/, covariance /koʊˈvæɹ.i.əns/, stochastic /stəˈkæstɪk/, asymptotic /ˌæsəm(p)ˈtɑtɪk/

Bu videoyla nasıl çalışılır

  1. Videonun tamamını konuşmadan bir kez dinleyin ve bilmediğiniz kelimeleri not edin.
  2. Normal hızda cümle cümle tekrar edin; ritminiz konuşmacıyla aynı olana kadar her cümleyi yineleyin.
  3. Kendinizi kaydedin ve orijinaliyle karşılaştırın; omega, intersection, multiply gibi kelimelere özellikle dikkat edin.

Gölgeleme Tekniği Nedir?

Gölgeleme, başlangıçta profesyonel tercüman eğitimi için geliştirilen ve çok dilli Dr. Alexander Arguelles tarafından popüler hale getirilen, bilim destekli bir dil öğrenme tekniğidir. Yöntem basit ama güçlüdür: ana dili İngilizce olan bir sesi dinler ve hemen yüksek sesle tekrar edersiniz — konuşmacıyı 1-2 saniye gecikmeyle takip eden bir gölge gibi. Pasif dinleme veya dilbilgisi alıştırmalarının aksine, gölgeleme beyninizi ve ağız kaslarınızı gerçek konuşma kalıplarını eşzamanlı olarak işlemeye ve yeniden üretmeye zorlar. Araştırmalar, telaffuz doğruluğu, tonlama, ritim, bağlı konuşma, dinleme anlama ve konuşma akıcılığını önemli ölçüde geliştirdiğini göstermektedir — bu da onu IELTS Konuşma hazırlığı ve gerçek dünya İngilizce iletişimi için en etkili yöntemlerden biri yapar.

Shadowing tekniği: adım adım eksiksiz rehberi okuyun →