शैडोइंग अभ्यास: The Limit (do not use L'Hospital rule) - वीडियो के साथ अंग्रेजी बोलना सीखें

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Okay, let's talk about the limit as theta goes to 0 of sine theta over theta.

Yes, we put 0 right here and right here, we end up with 0 over 0.

So maybe let's just go ahead and do the Lafittos rule.

Let's put on d, d theta, d, d theta.

So we are showing work, and our teacher will be happy, right?

So this is the limit as theta goes to 0.

And then when you differentiate sine theta, we get cosine theta.

And then when we differentiate theta, we just get 1.

And then now we can just put the 0 right here.

And in the end we are saying this is just cosine of zero.

Of course we can work this out.

This is just one.

That's it.

Took us about like 37 seconds.

That's it. And yeah.

Okay.

Has this ever happened to you guys?

You did this on the test.

But in the end you end up with a big X like that.

And you end up with zero points, zero marks for this question.

If this has happened to you, leave a comment down below.

And you might be wondering, what's so wrong with this?

Yes, we do the L'AbiDoc rule, and this is a 0 over 0 situation.

Is it because I didn't show work?

I forgot to put down this is a 0 over 0 situation at Lh.

Maybe I just forgot to show work.

Okay, now here's the problem.

The issue is that when you differentiate sine theta, Yes, the answer is cosine theta, but how do you know that?

Well, if you guys look back to the proof of the derivative of sine theta,

in fact, you need to first know what the limit as theta goes to 0 of sine theta over theta is first, before we can talk about the derivative of sine theta.

So, in other words, we cannot use derivative, we cannot use Lapidus' rule to figure this limit out, because otherwise, this is what we call the circular reasoning.

That's really bad, right?

Therefore, we must use another way to figure this out, and let's do it right here.

The way that we actually need to do it is by using geometry.

And first of all, let's just talk about we want to get the limit as theta goes to 0 plus.

And of course, let's put down side theta over theta.

Well, you'll see this is actually what we need, because later on we can also use this to figure out the limit as theta goes to 0 minus.

And you'll see you'll end up with the same answer, and then we can conclude the theta goes to 0 that limit.

Well, what we need to do first is, we are going to begin by looking at the unit circle.

And because we know theta is going to 0+, that means the angle is small and it's positive.

So we just need to consider the first quadrant.

So let me just draw the picture right here for you guys.

Let's say this right here is my unit circle.

And because unit circle, so we know this right here would be 1.

since the angle is small, so let me just put this down right here.

Right?

I just need a first quadrate.

That's all.

Now, I know this is one, of course.

Okay, next what we need is, let's first look at this arc.

And on the circle, we know that the arc has a formula, right?

The R-length formula.

We just need two things.

First, we need the R, the radius, and then next we need the angle theta in radians.

And of course, we are all doting out this angle theta is in radians already.

So in this case, I just need to do 1, which is the radius, times the radians theta angle right here.

So in other words, the arc length is just theta.

This represents the angle, this right here represents the length.

So that's the first thing that we need.

Next, what we'll do is, I will look at the inside and right here,

starting at this point, I'm going to draw a line straight down so that we can form a right angle.

I will also figure out a formula for this length.

And you can see that we have a right triangle now.

If you look at this right triangle, we do know the hypotenuse, and this will be the opposite side.

So let me just indicate this for you guys right here.

we have the opposite, that's the opposite, and then the hyponius is just 1.

And let me just indicate, over hyponius, and hyponius is 1.

Opposite over hyponius is what?

Yes, it's just sine, and of course we have that angle.

So therefore, this length is just sine theta.

Alright, we're making good progress.

Next, I will be looking at this point right here, which is 1 comma 0, and I will draw a line straight up.

In fact, this is also the tangent line.

You'll see tangent line.

Alright, so you see this right here, but in fact I'm not going to draw all the way, because what I will do is, I'm going to actually extend this right here, so I'll just put on some dot dot dot,

and then I will stop right here, alright, when they meet.

Well, in this case, I can create another right triangle But the problem is,

I don't know how big this is So I cannot use sign right here anymore, unfortunately, right?

But it's okay, because we know from here to here is 1

So if you just look at this bigger right triangle here This right here is once again the opposite

but this time this right here is the adjacent that we know

so just put on a d j

which in this case is also one what's opposite for adjacent yes it's tangent

so right here as told you guys earlier in fact that's the tangent line

so we get this right here equal to tangent theta like that cool Cool, huh?

Now, we have three things to compare.

The green length and then the red curve and also the blue length, right?

The blue line.

Well of course this right here is the smallest, this right here is the second, this right here is the biggest, right?

Because you see pretty much this right here is between of this and that.

From the picture you can see that's the biggest.

So let me just put this down right here for you guys.

First of all we know sine theta which is this length right here is the smallest.

Next, we have the r length, which is the theta, and then tangent theta is the biggest.

And, of course, we can put down some inequality.

It goes like this.

Well, theta changes.

In fact, theta is approaching zero plus.

So, in fact, let me also include the equal sign right here.

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This is still true, isn't it?

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Now, don't forget what we are trying to achieve.

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This is what we have.

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We want to achieve sine theta over theta, but we only have this.

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But it seems like theta should be in the denominator.

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So we are going to take the reciprocal of all this.

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And notice, everything right here, they are all positive because we have the theta is just a positive small number, right?

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So when I take the reciprocal, I get 1 over sine theta.

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And because everything is positive, you can just flip the inequality.

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And you get this right here, and then this right here is 1 over theta.

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And then you can just flip that as well.

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If you have 1 over tangent, that's just cotangent.

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In another word, you get cosine theta over sine theta.

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Well, well, I want to have the sine theta on the top, so why don't we just multiply everybody by sine theta right here?

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And when we do that, this times this is, of course, just 1, and then, of course, sine theta is positive.

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When you multiply by a positive number, the inequality stays.

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So I'll just put down sine theta on the top over theta, and then this times that, of course, the sine theta cancel we have this right here,

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which is just cosine theta.

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So this is what we have.

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What's next?

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Well, I'm trying to figure out the limit.

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From this inequality, I'll just take the limit as theta approaching 0 plus.

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So I will do it here.

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And then I will also do it here, the limit as theta approaching 0 plus.

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And then, of course, we also do it here.

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Right?

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Cool.

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This right here, 1 is always 1.

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So this is 1.

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You maintain the inequality.

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And then, this is exactly what we're trying to find out.

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I don't know yet, so let me just write this down.

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The limit as theta approaching 0 plus sin theta over theta.

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And then, this right here is what?

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You put 0 plus right here, cos 0 plus.

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Yes, we did it over there, but this was not legit.

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You get one.

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Now, you see, this limit is in between one and one.

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Therefore, we can use the squeeze theorem to argue that.

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So I'll just put this down by the squeeze theorem.

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Yes, T stands for stiff as well.

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right?

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Anyway, we can conclude that the limit as theta approaching zero plus of sine theta over theta,

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this right here, has to be equal to 1 as well, isn't it?

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And as you can see right here, we are done, and we got this right here.

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Cool.

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Yes.

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Now, we are not done yet.

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We also have to look at the zero minus version.

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So let me just put this down right here for you guys real quick.

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If you take a look of the limit as theta approaching 0 minus of sine theta over theta.

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Well, this right here is actually not that bad at all.

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Remember, when we have 0 plus, this is as saying, you know, theta is like about 0.0001.

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When you have 0 minus, it's just a negative of that version, pretty much, right?

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So, what you can do is, and depending on how much we're going to show,

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You can just look at this as sine of 0 minus, and then on the bottom you have 0 minus like this.

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Well, sine is an odd function.

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This right here is a negative number.

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So this right here, as I say, you can just take the negative on the outside because sine is an odd function.

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So you have negative of sine, and the input now, it will be the positive version, namely 0 plus.

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Likewise, 0 minus is as a negative of the 0 plus.

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Negative, negative, cancel.

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This right here gives you 1 because of that.

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It depends on how much work you have to show, but this right here, hopefully, is a good enough argument for many of you guys.

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And now, as we know, when we have the right limit and also the left limit equal to the same number,

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we can conclude that When we have the limit as theta goes to just zero of sine theta over theta,

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this right here has to be one.

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Finally, we did it.

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This is what I call the limit.

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This right here is the limit.

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Why?

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Because it happens a lot.

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Because this right here also happens a lot.

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It hurts a lot of students.

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And once again, leave a comment down below and let us know

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if this happened to you if you did that before or not.

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And in fact, I do feel guilty because sometimes I do this myself as well but I do it in my head.

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So as long as you don't write it down, we are good.

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Anyway, hopefully you guys all like this and let me know

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if you guys have any questions and if you guys are new to my channel, be sure to subscribe.

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You guys can find a lot more interesting my videos on my channel and thank you guys so much for that.

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And as always, that's it.

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इस वीडियो में शैडोइंग के लिए 181 वाक्य और 2020 शब्द हैं। बोला गया हिस्सा 12:07 लंबा है। वक्ता लगभग 167 शब्द प्रति मिनट की स्वाभाविक गति से बोलता है, जो रोज़मर्रा की बातचीत के करीब है। 86% शब्द अंग्रेज़ी के 3,000 सबसे आम शब्दों में से हैं; बाकी शब्द अभ्यास से पहले देख लेना अच्छा रहेगा।

इस वीडियो की मुख्य शब्दावली

वीडियो के 15 सीखने लायक शब्द, उच्चारण और अर्थ के साथ:

शब्द	उच्चारण	अर्थ
angle संज्ञा	/ˈæŋ.ɡəl/	कोण
minus	/ˈmaɪ.nəs/	कम, घटाकर
inequality संज्ञा	/ˌɪn.ɪˈkwɑ.lɪ.ti/	असमानता
triangle संज्ञा	/ˈtɹaɪˌæŋɡəl/	त्रिकोण, त्रिभुज
formula संज्ञा	/ˈfɔː.mjʊ.lə/	सूत्र, फ़ॉरमूला
conclude क्रिया	/kənˈkluːd/	समापन
indicate क्रिया	/ˈɪndɪˌkeɪt/	सूचित करना, संकेत करना
cancel क्रिया	/ˈkæn.sl̩/	निरस्त
squeeze क्रिया	/skwiːz/	निचोड़ना, दबाना
theorem संज्ञा	/ˈθiərəm/	प्रमेय
compare क्रिया	/kəmˈpɛɚ/	तौलना
curve संज्ञा	/kɚv/	चक्कर, घुमाव
circular विशेषण	/ˈsɜɹ.kjə.ləɹ/	वलयाकार, गोलाकार
geometry संज्ञा	/d͡ʒiˈɑ.mə.tɹi/	ज्यामिति, रेखागणित
sine संज्ञा	/saɪn/	ज्या

वीडियो में आने वाली फ़्रेज़ल वर्ब

शब्द	उच्चारण	अर्थ
go ahead क्रिया	/ˌɡoʊ əˈhɛd/	आगे बढ़ना

ध्यान देने योग्य उच्चारण

वक्ता 24 बार संक्षिप्त रूपों का प्रयोग करता है, जैसे don't, I'll, I'm। इन्हें वैसे ही छोटा बोलें जैसा आप सुनते हैं।

“th” की ध्वनियाँ: theorem /ˈθiərəm/, theta /ˈθiːtə/
लंबे शब्द — बलाघात सही रखें: inequality /ˌɪn.ɪˈkwɑ.lɪ.ti/, derivative /dɪˈɹɪvətɪv/, differentiate /dɪf.əˈɹɛn.ʃi.eɪt/, geometry /d͡ʒiˈɑ.mə.tɹi/, reciprocal /ɹɪˈsɪpɹək(ə)l/

इस वीडियो से अभ्यास कैसे करें

पहले बिना बोले पूरा वीडियो एक बार सुनें और जो शब्द नहीं आते उन्हें लिख लें।
0.75× गति से शुरू करें, एक-एक वाक्य की शैडोइंग करें, और सहज लगने पर सामान्य गति पर लौटें।
अपनी आवाज़ रिकॉर्ड करें और मूल से तुलना करें, ख़ासकर angle, minus, inequality जैसे शब्दों पर ध्यान दें।

शैडोइंग तकनीक क्या है?

शैडोइंग (Shadowing) एक विज्ञान-समर्थित भाषा सीखने की तकनीक है जो मूल रूप से पेशेवर दुभाषिया प्रशिक्षण के लिए विकसित की गई थी। विधि सरल लेकिन शक्तिशाली है: आप मूल अंग्रेज़ी ऑडियो सुनते हैं और तुरंत इसे ज़ोर से दोहराते हैं — जैसे वक्ता की छाया 1-2 सेकंड की देरी से। शोध से पता चलता है कि यह उच्चारण सटीकता, स्वर, लय, जुड़ी हुई ध्वनियाँ, सुनने की समझ और बोलने की प्रवाहशीलता में काफ़ी सुधार करता है।

शैडोइंग तकनीक: पूरी चरण-दर-चरण गाइड पढ़ें →

शैडोइंग अभ्यास: The Limit (do not use L'Hospital rule) - वीडियो के साथ अंग्रेजी बोलना सीखें

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