쉐도잉 연습: Statics: Lesson 46 - Distributed Loads Using Centroids - 영상으로 영어 말하기 배우기

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hey welcome back team today we're talking about distributed loads we've finished chapter set chapter 9

which was Centroids

and now I'm kind of going to jump you back to chapter 4 to talk about distributed loads

because really distribute loads I think it's kind of out of place until you talk about Centroids

and then they really make sense okay we know about Centroids center of volume, center of mass, center of area,

center of weight, center of pressure, right?

Distributed loads has a lot to do with that, okay?

So when you say a distributed load, what is a distributed load?

Well, it's like me standing on the floor, okay?

My weight is distributor over the size of my foot.

Or it's like this textbook.

If I lay this textbook on the table,

this textbook has weight, but that weight is not a point load or a concentrated load like we've been used to, right?

Like that.

That's what we're used to.

But this book actually has the weight spread out all over the whole thing

so that that weight is distributed across an area that's why we call it a distributed load some things

that you might see for

that um maybe maybe a snow load on a roof let's say you were designing a roof

or a building

and you needed to account for the snow load

now in texas where we are there we don't get a lot of snow

so we don't have to worry about that but

if you're up north then you have like a three or four foot storm that dumps that much snow

that could be a tremendous amount of weight on the roof.

If that kind of snow hit Texas,

it would collapse most buildings in Texas because they're just not designed to take that kind of weight on the roof.

So the distributed load looks something like this.

You'll see it given in some kind of weight per length.

In this case, 100 pounds per feet.

So for every foot I go, I'm going to accumulate 100 pounds of weight.

That's what the distributed load looks like.

And this is what we call a rectangular distributed load.

So it's even across the whole thing, okay?

So how do we deal with that?

I know how to deal with that, but I don't know how to deal with that, okay?

And so it would go something like this, right?

You would calculate the size of the distributed load by looking at how much of it you have.

So it's 100 pounds per feet over four feet.

So that would be 400 pounds.

And where do you apply that?

What we're doing here is we're converting a distributed load into a concentrated load just to simplify things

so that we can solve it as a regular old statics problem.

So that would be 400 pounds, right?

So you do 100 pounds per feet times four feet, right?

The feet cancel out and I'm left with just pounds, okay?

So that's where that comes from.

And then where do you apply it?

At the center, okay?

So distributed loads are all around us.

Let me give it to you this way.

Let's say that you want to go dancing, okay?

And you can go dancing, you can dance with me

or you could dance with lovely linda okay now i am full man size okay 220 pounds

that's full man size but lovely linda she's only 120 pounds okay

so who are you gonna dance with well before

we make up our mind let me tell you one thing me and Linda, we're both really bad dancers, okay?

And we're going to step on your foot, okay?

Now, I only go dancing in my cowboy boots, right?

And the heel of my cowboy boots is four inches by three inches, okay?

And so, lovely Linda, she only dances in her stiletto high heels because it makes her legs look good, you know what I mean?

And those little stilettos have a little high heel

that is a quarter of an inch by a quarter of an inch okay

now you're going to get stepped on i guarantee you that

because we're not that good at dancers okay

so let me tell you something you'll run into in solids

and that is stress okay

and stress is what we call the intensity of the force okay

so stress is p over a in other words the force divided by the area

that it's distributed over So in my case, you'd have 220 pounds divided by 3 times 4, 12 inches squared.

Now that's going to give me PSI, okay?

Where lovely Linda, lovely Linda over here is 120 pounds divided by a quarter times a quarter.

That is 0 .0625 inches squared.

And let's see what we get here.

So, if you're dancing with me, you get 220 divided by 12, you're going to feel 18 .3 PSI, okay?

but if you're dancing with linda over there 120 divided by 0 .0625 you're going to feel

1 ,920 psi okay now i don't know what the sheer stress of skin is

but you may be you know if i step on you it's going to hurt

but if she steps on you she may be standing on the floor like through your foot, right?

Punctured a hole right in you.

So, that's distributed load.

If you take a big load and you distribute it over a bigger area, the intensity of the force is much less,

whereas a smaller load even over a very small area, the intensity of the load is very high, okay?

So, when do we see this kind of stuff in real life?

Let's say, I've got me a truck drawn over here.

Let's say you go to the hardware store, okay?

You're building a new house and they're going to deliver it to you

and so what they do is they go out

and they stack up two by fours okay

and two by fours look like this okay and let's say that two by fours were i don't know

500 pounds per foot

and then the little guy at the hardware store thought he'd be clever

there was going to be some cinder blocks on there

so he stacked them like up high but then he went every row, he stacked them one less.

So he had like this triangular load here.

Okay.

Very clever little brick stacker guy.

And what we do on triangular loads is we only give you the tallest point.

So let's say that's 700 pounds per foot.

100

At this end, it's zero pounds per feet, isn't it?

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And then, I don't know, for some reason on that job site, they also were asking for a whole pallet full of helium okay maybe helium

102

and so that load is like this 200 pounds per feet

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but it's going upwards right it's it's pulling upwards okay so

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and if we look at this you might say well okay

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uh find the reactions on the tires okay

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so we could say over here maybe we have a by and then over here,

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I have an AY, and I could solve for those reaction forces on those tires

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if I can convert those distributed loads into concentrated loads.

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Well, this first one, let me just, let me, let's make up some numbers here.

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This looks like 15 feet.

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I'm going to do numbers that I can do in my head.

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How about that?

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20 feet.

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Okay.

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And this is 20 feet, which would make this back here 13 feet.

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Okay.

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It's a 53 foot trailer.

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That's how long, that's how long most flatbed tractor trailers are, 53 feet.

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Okay.

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So this bit up here is 500 times 20.

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That's going to be 10 ,000, isn't it?

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And where would I apply that?

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Right there.

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So that's 10 ,000 pounds.

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And I would apply that right in the center of

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that rectangle because the centroid of a rectangle is half the base, right?

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Then this guy, and all I'm doing, think about this as an area.

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Think about the 500 as the height, and the 20 as the width, and I'm finding the area.

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You can't go out with a tape measure and measure that area, but it's an area, okay?

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This area here is 700 tall by 20, but it's a triangle, so I'm going to treat it like an area.

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I've got to divide that by two, so that would be like 700 times 10, which would be 7 ,000.

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And where would you put that 7 ,000 pounds?

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Well, I put it like right there.

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Okay.

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Why right there?

136

Well, it's at one third the base of the triangle, right?

137

So this distance right here would be 20 over three.

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Okay.

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That's centroid stuff, isn't it?

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and then over here oh the only tricky part about this is the arrows are going up instead of down

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so this is 200 times 13 which would be 2600 and I would put that right there Okay.

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2 ,600 pounds.

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And it's in the middle of the 13.

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And so now, now I've got three concentrated loads where I used to have distributed loads.

145

I can solve that like a regular old statics problem, right?

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Take the moment at A and I got 400 times two rotating me negative.

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I got 500 times six rotating me negative plus BY times seven rotating me positive

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and just solve it like every problem we've done.

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So distributed load problems should be really easy for you if you know what a centroid is,

150

because all you gotta do is calculate the area of this shape, 100 times four, right?

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Apply that load at the centroid of that shape and then just work it like a regular old statics problem, okay?

152

So when I come back, we'll work one of those problems in the next video and maybe that'll make more sense to you.

153

So hope that helps.

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✨ 추천 영상

45 문장

이 레슨의 어휘와 말하기 포인트

이 말하기 레슨은 영상 “Statics: Lesson 46 - Distributed Loads Using Centroids”을(를) 바탕으로 합니다. 가장 자주 반복되는 단어는 다음과 같습니다: load, distributed, pounds, feet, weight. 이 영상에는 섀도잉할 문장 153개와 단어 1627개가 있습니다. 말하는 구간의 길이는 10:42입니다. 화자는 분당 약 152단어로, 일상 대화에 가까운 자연스러운 속도로 말합니다. 단어의 86%가 영어에서 가장 많이 쓰이는 3,000단어에 속합니다. 나머지는 연습 전에 미리 확인해 두세요. 전체 153문장 중 40문장이 질문이어서 의문문 억양과 짧은 대답을 연습하기에 좋습니다.

이 영상의 핵심 어휘

영상에 나오는 익혀 둘 만한 단어 15개를 발음, 뜻과 함께 정리했습니다.

단어	발음	뜻
divide 동사	/dɪˈvaɪd/	나누다, 가르다
solve 동사	/sɒlv/	해결하다
intensity 명사	/ɪnˈtɛnsɪti/	강도
stack 명사	/stæk/	무더기
heel 명사	/hil/	발뒤꿈치, 발뒤축
textbook 명사	/ˈtɛkst.bʊk/	교과서, 텍스트북
trailer 명사	/ˈtɹeɪlɚ/	트레일러
hardware 명사	/ˈhɑɹdˌwɛɹ/	하드웨어, 굳은모
boot 명사	/but/	장화, 목화
tire 동사	/ˈtaɪ̯ɚ/	피곤하다
dancer 명사	/ˈdænsəɹ/	댄서, 춤꾼
triangle 명사	/ˈtɹaɪˌæŋɡəl/	삼각, 삼각형
calculate 동사	/ˈkælkjʊleɪt/	정산하다, 계산하다
cowboy 명사	/ˈkaʊˌbɔɪ/	카우보이
guarantee 명사	/ˌɡæɹ.ənˈtiː/	보증

영상에 나오는 구동사

단어	뜻
come back 동사	돌아오다
go out 동사	나가다
go up 동사	올라가다

따라 말해 볼 만한 문장

영상에 나오는 짧고 완결된 문장으로, 일상 대화에서 그대로 쓸 수 있습니다:

That's what we're used to.
Let's say that you want to go dancing, okay?
Let's say you go to the hardware store, okay?
That's centroid stuff, isn't it?

주의할 발음

화자는 I'm, we're, you're 같은 축약형과 약화된 형태를 47번 사용합니다. 들리는 대로 짧게 발음하세요.

긴 단어 — 강세 위치에 주의: intensity /ɪnˈtɛnsɪti/, rectangular /ɹɛkˈtæŋɡjəlɚ/, triangular /tɹaɪˈæŋ.ɡjə.lɚ/, accumulate /əˈkjuːmjʊˌleɪt/

한국어 화자가 어려워하는 소리:

/f/ — ㅍ(/p/)으로 바꾸지 말고 윗니를 아랫입술에 대기: flatbed /ˈflætˌbɛd/, simplify /ˈsɪmplɪfaɪ/
/v/ — ㅂ(/b/)과 구별하기: divide /dɪˈvaɪd/, solve /sɒlv/, clever /ˈklɛv.ɚ/, convert /kənˈvɝt/
/z/ — ㅈ이 아니라 성대를 울리는 /s/: upwards /ˈʌpwɚdz/, whereas /(h)wɛɹˈæz/

이 영상으로 연습하는 방법

먼저 말하지 않고 영상을 끝까지 듣고 모르는 단어를 적어 둡니다.
0.75배속으로 한 문장씩 섀도잉을 시작하고, 익숙해지면 보통 속도로 돌아갑니다.
자신의 목소리를 녹음해 원본과 비교하고, divide, solve, intensity 같은 단어에 특히 주의합니다.

쉐도잉이란? 영어 실력을 빠르게 키우는 과학적 방법

쉐도잉(Shadowing)은 원래 전문 통역사 훈련을 위해 개발된 언어 학습 기법으로, 다언어 학자인 Dr. Alexander Arguelles에 의해 대중화된 방법입니다. 핵심 원리는 간단하지만 매우 강력합니다: 원어민의 영어를 들으면서 1~2초의 짧은 지연으로 즉시 소리 내어 따라 말하는 것——마치 '그림자(shadow)'처럼 화자를 따라가는 것입니다. 문법 공부나 수동적인 청취와 달리, 쉐도잉은 뇌와 입 근육이 동시에 실시간으로 영어를 처리하고 재현하도록 훈련합니다. 연구에 따르면 이 방법은 발음 정확도, 억양, 리듬, 연음, 청취력, 말하기 유창성을 크게 향상시킵니다. IELTS 스피킹 준비와 자연스러운 영어 소통을 원하는 분들에게 특히 효과적입니다.

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쉐도잉 연습: Statics: Lesson 46 - Distributed Loads Using Centroids - 영상으로 영어 말하기 배우기

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이 레슨의 어휘와 말하기 포인트

이 영상의 핵심 어휘

영상에 나오는 구동사

따라 말해 볼 만한 문장

주의할 발음

이 영상으로 연습하는 방법

쉐도잉이란? 영어 실력을 빠르게 키우는 과학적 방법